In 6 x 6, transportation problem degeneracy will not arise if the number of allocations areA36B> 11C11D< 11Answer: C. 11 Read Explanation: In Transporation Problem, the Number of Allocation to avoid Degeneracy is given by: Allocation=n1+n2−1;wheren1=NoofDestinationAvailable,n2=NoofSourceAvailable.Given:Allocation = n_1 + n_2 -1; where n_1 = No of Destination Available, n_2 = No of Source Available.Given: Allocation=n1+n2−1;wheren1=NoofDestinationAvailable,n2=NoofSourceAvailable.Given:n1=6,n2=6;Allocation=6+6−1TotalAllocation=11.n_1 = 6, n_2 = 6; Allocation = 6 + 6-1 Total Allocation = 11.n1=6,n2=6;Allocation=6+6−1TotalAllocation=11. Read more in App
