In a circle of radius 5 m, AB and CD are two equal and parallel chords of length 8 m each. What is the distance between the chords?

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A5 m

B6 m

C3 m

D8 m

Answer:

By Pythagoras theorem, 5² - 4² = 3²

The distance between the radius and chord is 3 m

The distance between two chords = 2 × 3 = 6 m

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