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When a shaft is subjected to combined twisting moment (T) and bending moment (M), the equivalent bending moment is equal to

AM2+T2\sqrt{M^2+T^2}

BM2+4T2\sqrt{M^2+4T^2}

C4M2+T2\sqrt{4M^2+T^2}

D12[M+M2+T2]\frac{1}{2}[M+\sqrt{M^2+T^2}]

Answer:

12[M+M2+T2]\frac{1}{2}[M+\sqrt{M^2+T^2}]

Read Explanation:

The equivalent bending moment for a shaft subjected to combined twisting moment and bending moment is given by Meq=12[M+M2+T2]M_{eq} =\frac{1}{2}[M+\sqrt{M^2+T^2}]This equation takes into account both the bending and twisting moments acting on the shaft and provides a single value for the equivalent bending moment.


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