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In ΔPQR, ∠PQR = 90°, PQ = 5 cm and QR = 12. What is the radius (in cm) of the circum circle of ΔPQR?

A6.5

B7.5

C13

D15

Answer:

A. 6.5

Read Explanation:

 

PR = √(PQ² + QR²)

PR = √(25 + 144) = 13 cm

Radius of circumcircle = hypotenuse/2 = 13/2 = 6.5 cm


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