Question

$P(x)=x^2+ax+b$ and P(-m)=P(-n)=0. Then (m+1)(n+1) is :

• A. a+b+1
• B. a-b+1
• C. a+b-1
• D. a-b-1

Answer 1

Answer:

A. a+b+1

P(a)=

(x-a) factor

P(-m)=0

(x--m)=(x+m)

P(-n)=0 (x+n)

$x^2+ax+b=(x+m)(x+n)$

Put x =1

(1+m)(1+n)

=1+a+b