Question

Ravi, Manish and Naveen alone can complete a work in 30 days, 15 days and 10 days respectively. They start the work together but Ravi leaves the work after 2 days of the starting of the work and Manish leaves the work after 3 days more. In how many days Naveen will complete the remaining work?

• A. 3
• B. 4
• C. 1
• D. 2

Answer 1

Answer:

C. 1

Solution: Given: Ravi can complete the work 30 days Manish can complete it in 15 days And Naveen can complete it in 10 days Concept: In this type of question always imagine the total work as LCM of time taken by individuals to perform the work. Formula used: Efficiency = Total work/Time taken Calculation: Let the total work be LCM of 30, 15, 10 i.e. 30 unit So efficiency of Ravi = 30/30 = 1 unit/day Efficiency of Manish = 30/15 = 2 unit/day Efficiency of Naveen = 30/10 = 3 unit/day Ravi work for 2 days and performed work = 2 × 1 = 2 unit Manish work for 5 days and performed work = 5 × 2 = 10 unit Naveen 5 day work = 5 × 3 = 15 unit Remaining work = 30 – (2 + 10 + 15) = 3 unit ∴ Time taken by Naveen to complete the remaining work = 3/3 = 1 day