Challenger App

No.1 PSC Learning App

1M+ Downloads
Solution of the linear inequalities 2x+5>1 and 3x-4≤5 is :

A(-2,3]

B[-2,3)

C(-∞,-2)

D[3,∞)

Answer:

A. (-2,3]

Read Explanation:

2x+5>1 2x>1-5 x>-4/2 x>-2 3x-4≤5 3x≤5+4 3x≤9 x≤9/3 x≤3 -2<x≤3 (-2,3]


Related Questions:

If a + b = 8 and a + a2 b + b + ab2 = 128 then the positive value of a3 + b3 is:

Two positive numbers differ by 1280. When the greater number is divided by the smaller number, the quotient is 7 and the remainder is 50. The greater number is:
a+b =10, ab= 32 ആയാൽ a² + b² എത്രയാണ്?

The value of 5.35×5.35×5.35+3.65×3.65×3.6553.5×53.5+36.5×36.553.5×36.5\frac{5.35\times{5.35}\times{5.35}+3.65\times{3.65}\times{3.65}}{53.5\times{53.5}+36.5\times{36.5}-53.5\times{36.5}} is:

A statement is given, followed by four conclusions given in the options. Find out which conclusion is true based on the given statement. Statement: H=W>F≥S≥T>Y