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If x2+1/x2=66 x^2+1/x^2=66 findx−1/xx-1/x

A10

B9

C8

D6

Answer:

C. 8

Read Explanation:

(x−1/x)2=x2+2−1/x2(x-1/x)^2=x^2+2-1/x^2

(x−1/x)2=x2+1/x2−2=66−2=64(x-1/x)^2=x^2+1/x^2-2=66-2=64

x−1/x=64=8x-1/x=\sqrt{64}=8

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തുടർച്ചയായ രണ്ട് ഇരട്ട സംഖ്യകളുടെ വർഗ്ഗങ്ങളുടെ വ്യത്യാസം 68 ആയാൽ സംഖ്യകൾ ഏത്?