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If a + b =10 and ab = 16 finda3+b3a^3+b^3

A480

B520

C680

D720

Answer:

B. 520

Read Explanation:

(a+b)3=a3+b3+3ab+3ab2(a+b)^3=a^3+b^3+3a^b+3ab^2

a3+b3=(a+b)33ab(a+b)a^3+b^3=(a+b)^3-3ab(a+b)

=1033×16(10)=10^3-3\times16(10)

=1000480=1000-480

=520=520


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