If a + b =10 and ab = 16 finda3+b3a^3+b^3a3+b3 A480B520C680D720Answer: B. 520 Read Explanation: (a+b)3=a3+b3+3ab+3ab2(a+b)^3=a^3+b^3+3a^b+3ab^2(a+b)3=a3+b3+3ab+3ab2a3+b3=(a+b)3−3ab(a+b)a^3+b^3=(a+b)^3-3ab(a+b)a3+b3=(a+b)3−3ab(a+b) =103−3×16(10)=10^3-3\times16(10)=103−3×16(10) =1000−480=1000-480=1000−480 =520=520=520 Read more in App