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If (a+1/a3)2=16(a+1/a-3)^2=16 then find a3+1/a3a^3+1/a^3

A413

B343

C322

D143

Answer:

C. 322

Read Explanation:

(a+1/a3)2=16(a+1/a-3)^2=16

a+1/a3=16=4a+1/a-3=\sqrt{16}=4

a+1/a3=4a+1/a-3=4

a+1/a=4+3=7a+1/a=4+3=7

a3+1/a3=733×7a^3+1/a^3=7^3-3\times7

=34321=343-21

=322=322

if (a+1/a3)2=k(a+1/a-3)^2=k then a3+1/a3=k33ka^3+1/a^3=k^3-3k


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