If (a+1/a−3)2=16(a+1/a-3)^2=16(a+1/a−3)2=16 then find a3+1/a3a^3+1/a^3a3+1/a3 A413B343C322D143Answer: C. 322 Read Explanation: (a+1/a−3)2=16(a+1/a-3)^2=16(a+1/a−3)2=16a+1/a−3=16=4a+1/a-3=\sqrt{16}=4a+1/a−3=16=4 a+1/a−3=4a+1/a-3=4a+1/a−3=4 a+1/a=4+3=7a+1/a=4+3=7a+1/a=4+3=7a3+1/a3=73−3×7a^3+1/a^3=7^3-3\times7a3+1/a3=73−3×7=343−21=343-21=343−21=322=322=322if (a+1/a−3)2=k(a+1/a-3)^2=k(a+1/a−3)2=k then a3+1/a3=k3−3ka^3+1/a^3=k^3-3ka3+1/a3=k3−3k Read more in App