Challenger App

No.1 PSC Learning App

1M+ Downloads

If (a+1/a3)2=16(a+1/a-3)^2=16 then find a3+1/a3a^3+1/a^3

A413

B343

C322

D143

Answer:

C. 322

Read Explanation:

(a+1/a3)2=16(a+1/a-3)^2=16

a+1/a3=16=4a+1/a-3=\sqrt{16}=4

a+1/a3=4a+1/a-3=4

a+1/a=4+3=7a+1/a=4+3=7

a3+1/a3=733×7a^3+1/a^3=7^3-3\times7

=34321=343-21

=322=322

if (a+1/a3)2=k(a+1/a-3)^2=k then a3+1/a3=k33ka^3+1/a^3=k^3-3k


Related Questions:

തുടർച്ചയായ രണ്ട് ഇരട്ട സംഖ്യകളുടെ വർഗ്ഗങ്ങളുടെ വ്യത്യാസം 68 ആയാൽ സംഖ്യകൾ ഏത്?

A=x1x+1A=\frac{x-1}{x+1}, then the value of A1AA-\frac{1}{A} is:

If the sum and product of two numbers are respectively 40 and 375, then their difference is
(3x - 6)/x - (4y -6)/y + (6z + 6)/z = 0 ആയാൽ (1/x - 1/y - 1/z) എത്രയാണ്?

If x4+1x4=25716x^4+\frac{1}{x^4}=\frac{257}{16} then find 813(x3+1x3)\frac{8}{13}(x^3+\frac{1}{x^3}), where x>0.