If (3x - 6)/x - (4y - 6)/y + (6z + 6)/z = 0, then what is (1/x - 1/y

Challenger App

★

1M+ Downloads

(3x - 6)/x - (4y -6)/y + (6z + 6)/z = 0 ആയാൽ (1/x - 1/y - 1/z) എത്രയാണ്?

B6/5

C5/6

Answer:

(3x - 6)/x - (4y -6)/y + (6z + 6)/z = 0 3 - 6/x - 4 + 6/y + 6 + 6/z = 0 6/x - 6/y - 6/z = 5 1/x - 1/y - 1/z = 5/6

Related Questions:

If $x =\sqrt{3} - 1$ and $y =\sqrt{3}+1$ then $\frac{(x^4-y^4)}{(x+y)^2}$ is equal to ?

If (m-n)²=64 and mn=180, then (m+n)² is: