Is $(x-2)^2+1=2x-3$ a quadratic equation, then find the roots

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A3,1

B4,2

C0,5

D1,4

Answer:

$(x-2)^2+1=2x-3$

$x^2-4x+4+1=2x-3$

$x^2-4x+5-2x+3=0$

$x^2-6x+8=0$

Which is a quadratic equation.

$a=1,b=-6,c=8$

Sum of roots = -6

Product of roots = 8

$\implies{x=4, 2}$

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