If x2+1/x2=79x ^ 2 + 1 / x ^ 2 = 79x2+1/x2=79 find the value of x+1/xx + 1 / xx+1/x A10B9C8D7Answer: B. 9 Read Explanation: (x+1/x)2=x2+1/x2+2(x+1/x)^2=x^2+1/x^2+2(x+1/x)2=x2+1/x2+2(x+1/x)2=79+2(x+1/x)^2=79+2(x+1/x)2=79+2 (x+1/x)2=81(x+1/x)^2=81(x+1/x)2=81 x+1/x=81=9x+1/x=\sqrt{81}=9x+1/x=81=9 Read more in App