If xy = 16 and $x^2+y^2=32$then the value of x+y=?

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If xy = 16 and $x^2+y^2=32$ then the value of x+y=?

A10

Answer:

$(x+y)^2=x^2+y^2+2xy$

$(x+y)^2=32+2\times16$

$=32+32=64$

$(x+y)=\sqrt{64}=8$

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