Solve, (x−1)2=[4(x−4)]2(x-1)^2 = [4\sqrt{(x-4)}]^2(x−1)2=[4(x−4)]2 A13, 5B3.4C9, 4D21, 15Answer: A. 13, 5 Read Explanation: x2−2x+1=16(x−4)x^2-2x+1 = 16(x-4)x2−2x+1=16(x−4)x2−2x+1=16x−64x^2-2x+1 = 16x-64x2−2x+1=16x−64 x2−18x+65=0x^2-18x+65 = 0 x2−18x+65=0(x−13)(x−5)=0(x-13)(x-5) = 0 (x−13)(x−5)=0Hence, x = 13 and x = 5 Read more in App
