Question

Solve, $(x-1)^2 = [4\sqrt{(x-4)}]^2$

• A. 13, 5
• B. 3.4
• C. 9, 4
• D. 21, 15

Answer 1

Answer:

A. 13, 5

$x^2-2x+1 = 16(x-4)$

$x^2-2x+1 = 16x-64$

$x^2-18x+65 = 0$

$(x-13)(x-5) = 0$

Hence, x = 13 and x = 5