f(x,y)=xy2+3x+2y3+logxf(x,y) = xy^2+3x+2y^3+logxf(x,y)=xy2+3x+2y3+logx എങ്കിൽ fx=?</span>f_x = ?</span>fx=?</span> Ay2+1x+3y^2+ \frac{1}{x} + 3y2+x1+3B1x+3\frac{1}{x} + 3x1+3C1x−3\frac{1}{x} -3x1−3Dy2−1x−3y^2-\frac{1}{x} -3y2−x1−3Answer: y2+1x+3y^2+ \frac{1}{x} + 3y2+x1+3 Read Explanation: f(x,y)=xy2+3x+2y3+logxf(x,y) = xy^2+3x+2y^3+logxf(x,y)=xy2+3x+2y3+logxfx=y2+3+0+1x=y2+1x+3f_{x} = y^2 + 3 + 0 + \frac{1}{x} = y^2 + \frac{1}{x} + 3fx=y2+3+0+x1=y2+x1+3 Read more in App
