If xy = 16 and x2 + y2 = 32, then the value of (x + y) is: A±10B±4C±8D±6Answer: C. ±8 Read Explanation: Solution:Given:x2 + y2 = 32 and xy = 16Formula:(x + y)2 = x2 + y2 + 2xyCalculation:(x + y)2 = x2 + y2 + 2xy⇒ (x + y)2 = 32 + 2 ×\times× 16 ⇒ (x + y)2 = 32 + 32⇒ (x + y)2 = 64⇒ (x + y) = ±8 Read more in App