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What is the value of

tan30+cot30sec30+tan30×sin30\frac{tan30^\circ+cot30^\circ}{sec30^\circ+tan30^\circ}\times sin30^\circ

A232-\sqrt{3}

B2+32+\sqrt{3}

C23\frac{2}{3}

D23\frac{-2}{3}

Answer:

23\frac{2}{3}

Read Explanation:

Solution:

Calculation:

tan30∘ = 1/√3 

cot30∘ = √3 

sec30∘ =  2/√3 

sin30∘ = 1/2

tan30+cot30sec30+tan30×sin30\frac{tan30^\circ+cot30^\circ}{sec30^\circ+tan30^\circ}× sin30^\circ

13+323+13\frac{{1\over\sqrt3}+\sqrt3}{{2\over\sqrt3}+{1\over\sqrt3}}

⇒ {(1 + 3)/√3} / {(2 + 1)/√3} ×12\frac{1}{2}

⇒ {4/√3} / {3/√3} ×12\frac{1}{2}

⇒ 4/3 × 1/2

⇒ 2/3

∴ The correct answer is option (3).


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