Challenger App

No.1 PSC Learning App

1M+ Downloads

What is the value of

tan30+cot30sec30+tan30×sin30\frac{tan30^\circ+cot30^\circ}{sec30^\circ+tan30^\circ}\times sin30^\circ

A232-\sqrt{3}

B2+32+\sqrt{3}

C23\frac{2}{3}

D23\frac{-2}{3}

Answer:

23\frac{2}{3}

Read Explanation:

Solution:

Calculation:

tan30∘ = 1/√3 

cot30∘ = √3 

sec30∘ =  2/√3 

sin30∘ = 1/2

tan30+cot30sec30+tan30×sin30\frac{tan30^\circ+cot30^\circ}{sec30^\circ+tan30^\circ}× sin30^\circ

13+323+13\frac{{1\over\sqrt3}+\sqrt3}{{2\over\sqrt3}+{1\over\sqrt3}}

⇒ {(1 + 3)/√3} / {(2 + 1)/√3} ×12\frac{1}{2}

⇒ {4/√3} / {3/√3} ×12\frac{1}{2}

⇒ 4/3 × 1/2

⇒ 2/3

∴ The correct answer is option (3).


Related Questions:

A triangle is to be drawn with one side 6cm and an angle on it is 30 what should be the minimum length of the side opposite to this angle?

The value of 2tan601+tan260=\frac{2tan60}{1+tan^260}=

If sinx=1237sinx=\frac{12}{37} , then what is the value of tan x?

The value of sin252+2+sin2384cos2435+4cos247\frac{{{{\sin }^2}{}52^\circ + 2 + {{\sin }^2}{{ }}38^\circ }}{{4{}{{\cos }^2}43^\circ - 5 + 4{{\cos }^2}{{}}47^\circ }}

Find the area of the triangle where AB= 4, BC = 6, ∠CAB = 120

1000114764.jpg