Find the area of the triangle where AB= 4, BC = 6, ∠CAB = 120

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A12

B6√3

C8√3

D10

Answer:

Area = 1/2 × ab × sinx : x< 90

= 1/2 × ab × sin(180 - x) : x>90

= 1/2 × 4 × 6 × sin (180 - 120)

= 1/2 × 24 × sin 60

= 12 ×√3/2

= 6√3

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