App Logo

No.1 PSC Learning App

1M+ Downloads

What is the remainder when (255+323)(2^{55}+3^{23}) is divided by 5?

A0

B1

C2

D3

Answer:

A. 0

Read Explanation:

Shortcut Trick

(255+323)(2^{55}+3^{23})

Power of 2 = 55÷455\div{4} = Remainder is 3 

Power of 3 = 23÷423\div{4} = Remainder is 3 

Then,

(23 + 33) ÷ 5

⇒ (8 + 27) ÷ 5 

⇒ 35 ÷ 5 = 7, which means here remainder is 0.

Alternate Method

We can write, 255 = (24)13 × 23

⇒ Unit digit (255) = Unit digit (1613 ×\times 8)

⇒ Unit digit (255) = Unit digit (613 ×\times 8)

⇒ Unit digit (255) = Unit digit (6 ×\times 8) = 8

Similarly

,

We can write, 323 = (34)5 ×\times 33

⇒ Unit digit (323) = Unit digit (815 ×\times 7)

⇒ Unit digit (323) = Unit digit (15 ×\times 7)

⇒ Unit digit (323) = 7

Now,

Unit digit (255 + 323) = Unit digit (8 + 7) = 5

∵ When 5 is divided by 5, the remainder is 0

∴ When (255 + 323) is divided by 5, the remainder is 0.


Related Questions:

If a seven-digit number 7x634y2 is divisible by 88, then for the largest value of y, what is the difference of the values of x and y?
Find the number of all prime numbers less than 55?

Find the number of zeroes at the end of the product of the expression (152×126×504×42)(15^2\times{12^6}\times{50^4}\times{4^2}) ?

താഴെ കൊടുത്ത സംഖ്യകളിൽ 12 ന്റെ ഗുണിതമേത് ?
What is the least natural number that should be added to 1135 so that the sum is completely divisible by 3, 4, 5, and 6?