Suppose a bus covers a distance at 40 kmp/h and an equal distance at 60 kmp/h. Then what is the average speed during the whole journey ?A55B45C48D50Answer: C. 48 Read Explanation: To find the average speed of a journey where two equal distances are covered at different speeds, use the harmonic mean formula:Average Speed=2xyx+y\text{Average Speed} = \frac{2xy}{x + y}Average Speed=x+y2xyWhere:xxx = speed for the first half = 40 km/hyyy = speed for the second half = 60 km/hSubstitute the values into the formula:Average Speed=2×40×6040+60\text{Average Speed} = \frac{2 \times 40 \times 60}{40 + 60}Average Speed=40+602×40×60Multiply the numbers in the numerator:2×40×60=48002 \times 40 \times 60 = 48002×40×60=4800Add the numbers in the denominator:40+60=10040 + 60 = 10040+60=100Divide the numerator by the denominator:Average Speed=4800100=48 km/h\text{Average Speed} = \frac{4800}{100} = \mathbf{48\text{ km/h}}Average Speed=1004800=48 km/hFinal AnswerThe average speed during the whole journey is 48 km/h. Read more in App