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Suppose a bus covers a distance at 40 kmp/h and an equal distance at 60 kmp/h. Then what is the average speed during the whole journey ?

A55

B45

C48

D50

Answer:

C. 48

Read Explanation:

To find the average speed of a journey where two equal distances are covered at different speeds, use the harmonic mean formula:

Average Speed=2xyx+y\text{Average Speed} = \frac{2xy}{x + y}

Where:

  • xx = speed for the first half = 40 km/h

  • yy = speed for the second half = 60 km/h


  1. Substitute the values into the formula:
    Average Speed=2×40×6040+60\text{Average Speed} = \frac{2 \times 40 \times 60}{40 + 60}

  2. Multiply the numbers in the numerator:
    2×40×60=48002 \times 40 \times 60 = 4800

  3. Add the numbers in the denominator:
    40+60=10040 + 60 = 100

  4. Divide the numerator by the denominator:
    Average Speed=4800100=48 km/h\text{Average Speed} = \frac{4800}{100} = \mathbf{48\text{ km/h}}


Final Answer

The average speed during the whole journey is 48 km/h.


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