Challenger App

No.1 PSC Learning App

1M+ Downloads
The area of a field in the shape of a regular hexagon is 3750√3 m2. What will be the cost (in Rs.) of putting fence around it at Rs. 29 per meter?

A10,150

B7,250

C9,425

D8,700

Answer:

D. 8,700

Read Explanation:

Solution: Given: Area of hexagonal field is 3750√3 m2 Cost of fencing is Rs. 29 per meter Formula Used: Area of hexagon = 6 × (√3)/4 × a2 Perimeter of a hexagon = 6 × a Where a is a side of hexagon. Cocnept Used: Fencing is done around the boundaries of any field. i.e. We need to calculate the perimeter of a field, To find the length of fencing. Calculation: Area of hexagon = 6 × (√3)/4 × a2 ⇒ 3750√3 = 6 × (√3)/4 × a2 ⇒ 3750 = 6 × 1/4 × a2 ⇒ (3750 × 4)/6 = a2 ⇒ 2500 = a2 ⇒ a = 50 Perimeter of a hexagonal field = 6 × a ⇒ Perimeter of a hexagonal field = 6 × 50 ⇒ Perimeter of a hexagonal field = 300 meter. Cost of fencing is Rs. 29 per meter ⇒ Total cost of fencing is, ⇒ 29 × 300 ⇒ 8,700 Rs. ∴ Total cost of fencing is Rs. 8,700.


Related Questions:

ഒരു മീറ്ററിന്റെ പകുതിയുടെ പകുതി എത്ര?

The area of a rectangle is thrice that of a square. The length of the rectangle is 20 cm and the breadth of the rectangle is 32\frac{3}{2} times that of the side of the square. The side of the square, (in cm) is

ഒരു ബഹുഭുജത്തിൻ്റെ ആന്തര കോണുകളുടെ തുക 1800 ആയാൽ ബഹുഭുജത്തിൻ്റെ വശങ്ങളുടെ എണ്ണം എത്ര?
ഒരു സമചതുരത്തിന്റെ ചുറ്റളവ് 52 സെ.മീ. ആയാൽ ഒരു വശത്തിന്റെ നീളമെത്ര ?
The area of sector of a circle of radius 36 cm is 72π sqcm. The length of the corresponding arc of the sector is?