The area of a sector of a circle with radius 7 cm and central angle 90° is :A38.5 cm²B35.2 cm²C40.5 cm²D42.62 cm²Answer: A. 38.5 cm² Read Explanation: Area of a sector:Area=θ360∘×πr2\text{Area}=\frac{\theta}{360^\circ}\times \pi r^2Area=360∘θ×πr2Given:(r=7) cm(θ=90∘)(\theta=90^\circ)(θ=90∘)=90360×π×72=\frac{90}{360}\times \pi \times 7^2=36090×π×72=14×π×49=\frac{1}{4}\times \pi \times 49=41×π×49=49π4=\frac{49\pi}{4}=449πUsing (π=227):(\pi=\frac{22}{7}):(π=722):494×227\frac{49}{4}\times \frac{22}{7}449×722=1544=\frac{154}{4}=4154=38.5=38.5=38.5So, the area of the sector is:38.5 cm2\boxed{38.5\ \text{cm}^2}38.5 cm2 Read more in App