Question

The diagonal of a square is $4\sqrt{2}cm$. The diagonal of anothersquare whose area is doublethat of the first square is :

• A. $$8\sqrt{2} cm$$
• B. 16 cm
• C. $$\sqrt{32} cm$$
• D. 8 cm

Answer 1

Answer:

D. 8 cm

Side of the first square $=\frac{1}{\sqrt{2}}\times{4\sqrt{2}}=4 cm$

Area of 1st Square$= 4^2=16cm^2$

Area of 2nd square $=2\times{16}=32cm^2$

Its Side $= \sqrt{32}=4\sqrt{2}cm$

Required diagonal $= \sqrt{2}\times{4\sqrt{2}}=8cm$