Question

The perimeter of two squares are 40 cm and 24 cm. The perimeter of a third square , whose area is equal to the difference of the area of these squares, is

• A. 34 cm
• B. 32 cm
• C. 38 cm
• D. 30 cm

Answer 1

Answer:

B. 32 cm

Side of the first square $=\frac{40}{4}=10cm$

Side of the second square $=\frac{24}{4}=6cm$

Difference of the area of these squares

$= (10\times{10}-6\times{6}) cm^2$

$= (100 -36) cm^2$

$= 64 cm^2$

Area of the third square = 64 cm²

Side of third square $=\sqrt{64}=8cm$

Perimeter of this square = (4 × 8) cm = 32 cm