Solution:
Given:
The sides of two squares [(S1) and (S2)] are in the ratio 4 : 3
The sum of their Areas is 225 cm2.
Formula used:
The Perimeter (P) of the smaller square = 4 (side)
Area of a Square = (side)2
Calculations:
According to the question,
S1/S2 = 4/3
⇒ S1 = 4(S2)/3, and
Then Areas of the Square:
(S1)2 + (S2)2 = 225
⇒ (4S2/3)2 + (S2)2 = 225
⇒ 16(S2)2/9 + (S2)2 = 225
⇒ 25 (S2)2/9 = 225
⇒ 25 (S2)2 = 2025
⇒ (S2)2 = 2025/25
⇒ (S2)2 = 81 = 9 cm
⇒ S1 = (4 × 9)/3
⇒ S1 = 36/3 = 12 cm
The perimeter of the smaller square:
⇒ P = 4 × 9 = 36 cm
∴ The perimeter of the smaller square will be 36 cm.