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The product of two numbers is 5292 and their H.C.F. is 21. The number of such pairs is:

A1

B4

C2

D3

Answer:

C. 2

Read Explanation:

Let the two numbers be 21a and 21b(since hcf = 21 and gcd =1)

21a×21b21a\times21b = 5292

441ab = 5292

ab=5292441 ab = \frac{5292}{441}

ab = 12 and gcd(a,b) = 1

factor pairs of 12:

(1,12),(2,6),(3,4)

valid pairs are (1,12),(3,4)

each gives a pair of numbers (21,252)(63,84)

so total number of such pairs = 2


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