Question

The smallest natural number which is divisible by 11, 6, 55 and 9 is:

• A. 921
• B. 990
• C. 1054
• D. 1032

Answer 1

Answer:

B. 990

We need the LCM (Least Common Multiple) of 11, 6, 55, and 9.

Prime factorization:

• 11 = 11

• 6 = 2 × 3

• 55 = 5 × 11

• 9 = 3²

Take highest powers of all primes:

• 2, 3², 5, 11

LCM = $( 2 \times 9 \times 5 \times 11 = 990 )$

Answer: 990