Question

The state of an electron in an atom with principal quantum number n = 3 and orbital quantum number l = 2 is

• A. 3s
• B. 4d
• C. 3p
• D. 3d

Answer 1

Answer:

D. 3d

• The state of an electron with principal quantum number $n = 3$ and orbital quantum number $l = 2$ is $3d$.

• Principal Quantum Number ($n = 3$): Represents the main energy level or shell

• Orbital Quantum Number ($l = 2$): Represents the subshell type, where the numerical values correspond to letter designations.

• l=0 s subshell

• l=1 p subshell

• l=2 d subshell

• l=3 f subshell

• Combining $n = 3$ and $l = 2$ gives the subshell designation $3d$.