Question

The sum of squares of three consecutive positive numbers is 365 the sum of the numbers is

• A. 30
• B. 33
• C. 36
• D. 45

Answer 1

Answer:

B. 33

Let three numbers be x, (x+1), (x+2) =x²+(x+1)²+(x+2)² =365 =3x² +6x+5-365-0 = x² +2x-120 = 0 = x² +12x-10x - 120 =0 =(x-10)(x+12) so, x = 10 or -12 Numbers are 10, 11, 12