Question

The sum of the present ages of a father and his daughter is 80 years. Eight years ago, the father's age was seven times the age of his daughter. Eight years from now, what will be the daughter's age?

• A. 20 years
• B. 18 years
• C. 22 years
• D. 24 years

Answer 1

Answer:

D. 24 years

father age = F

daughter age = D

$F+D=80$-------------------1

8 years ago

$F-8=7(D-8)$

$F-8=7D-56$

$F=7D-48$------------------------2

2 in 1

$7D-48+D=80$

$8D=80+48$

$8D=128$

$D=16$

age of daughter after 8 years =16+8=24