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Today 10th May 2018 is a Thursday. What day of the week will it be on 25 December,2018?

AWednesday

BSunday

CMonday

DTuesday

Answer:

D. Tuesday

Read Explanation:

It will be a Tuesday.

To find the day of the week, we need to count the total number of days between May 10, 2018, and December 25, 2018, and then find the remainder when divided by 7 (called "odd days").

Step 1: Count the remaining days in each month

* May: 21 days remaining (31 total days - 10)

* June: 30 days

* July: 31 days

* August: 31 days

* September: 30 days

* October: 31 days

* November: 30 days

* December: 25 days (up to the target date)

Step 2: Convert days into odd days (Remainder after dividing by 7)

Instead of adding large numbers, divide each month's days by 7 and use the remainder:

* May: 21÷7=remainder 021 \div 7 = \text{remainder } \mathbf{0}

* June: 30÷7=remainder 230 \div 7 = \text{remainder } \mathbf{2}

* July: 31÷7=remainder 331 \div 7 = \text{remainder } \mathbf{3}

* August: 31÷7=remainder 331 \div 7 = \text{remainder } \mathbf{3}

* September: 30÷7=remainder 230 \div 7 = \text{remainder } \mathbf{2}

* October: 31÷7=remainder 331 \div 7 = \text{remainder } \mathbf{3}

* November: 30÷7=remainder 230 \div 7 = \text{remainder } \mathbf{2}

* December: 25÷7=remainder 425 \div 7 = \text{remainder } \mathbf{4}

Step 3: Total the odd days

Total Odd Days=0+2+3+3+2+3+2+4=19\text{Total Odd Days} = 0 + 2 + 3 + 3 + 2 + 3 + 2 + 4 = \mathbf{19}

Now, simplify 19 days into weeks:

19÷7=2 weeks and 5 odd days19 \div 7 = 2 \text{ weeks and } \mathbf{5 \text{ odd days}}

Step 4: Add the odd days to the given day

Count 5 days forward from Thursday:

1. Friday

2. Saturday

3. Sunday

4. Monday

5. Tuesday


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