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What are the two signs to be interchanged for making the following equation correct ?

[{(44−36)+(4×4)}÷(1+5)]×2=8\left[ \left\{ (44 \mathbf{-} 36) \mathbf{+} (4 \times 4) \right\} \div (1 \mathbf{+} 5) \right] \times 2 = 8

A+ , x

B+ , ÷

C+ , -

Dx , ÷

Answer:

C. + , -

Read Explanation:

The two signs that need to be interchanged to make the equation correct are ++ and −-.

Substitute every ++ with −- and every −- with ++ in the original equation:

[{(44−36)+(4×4)}÷(1+5)]×2=8\left[ \left\{ (44 \mathbf{-} 36) \mathbf{+} (4 \times 4) \right\} \div (1 \mathbf{+} 5) \right] \times 2 = 8

Follow the BODMAS/PEMDAS rule (brackets first):

  1. Solve the innermost parentheses:

    • 44−36=844 - 36 = 8

    • 4×4=164 \times 4 = 16

    • 1+5=61 + 5 = 6

  2. Substitute these values back into the curly brackets:

    • [{8+16}÷6]×2\left[ \{ 8 + 16 \} \div 6 \right] \times 2

    • [24÷6]×2\left[ 24 \div 6 \right] \times 2

  3. Solve the square brackets:

    • 24÷6=424 \div 6 = 4

  4. Perform the final multiplication:

    • 4×2=84 \times 2 = 8

Since 8=88 = 8, the equation becomes completely correct.


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