Numbers divisible by 11 between 100 and 250 form an arithmetic sequence.
Find first and last terms
First multiple of 11 ≥ 100 → (11×10=110)
Last multiple of 11 ≤ 250 → (11×22=242)
Use property of arithmetic sequence
The average of equally spaced numbers =
2first term+last term
=2110+242=2352=176
Final Answer:
176