Question

What is the eccentricity of the conic with equation 3y²-x²=108

• A. 3
• B. 1.5
• C. 10/3
• D. 2

Answer 1

Answer:

D. 2

$\frac{3y^2}{108}-\frac{x^2}{108}=1$

$\frac{y^2}{6}-\frac{x^2}{(6\sqrt3)^2}=1$

$e=\frac{\sqrt{a^2+b^2}}{a}$

$a=6;b=6\sqrt3$

$e=\frac{\sqrt{36+108}}{6}=\frac{12}{6}=2$