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What is the remainder when 1! +2! +3! +…+99! +100! Is divided by 12?

A11

B9

C8

D0

Answer:

B. 9

Read Explanation:

After 3! all the number is divisible by 12 . From 4! onwards all the terms Perfectly divisible by 12 . This makes 4!+……..+100! Term remainder is 0 . So 1!+2!+3!=9 will remain only , hence the answer will be 9.


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