What is the remainder when 1! +2! +3! +…+99! +100! Is divided by 12?
A11
B9
C8
D0
Answer:
B. 9
Read Explanation:
After 3! all the number is divisible by 12 .
From 4! onwards all the terms Perfectly divisible by 12 .
This makes 4!+……..+100! Term remainder is 0 .
So 1!+2!+3!=9 will remain only , hence the answer will be 9.