Challenger App

No.1 PSC Learning App

1M+ Downloads
X and Y are two alloys of Gold and Platinum prepared by mixing the metals in the ratio of 5:2 and 5:7, respectively. If we melt equal quantities of the alloys to form a third alloy Z, then the ratio of the quantity of Gold to the quantity of Platinum in Z will be:

A84:73

B95:73

C95:84

D73:95

Answer:

B. 95:73

Read Explanation:

X=5:2X=5:2

Y=5:7Y=5:7

taking equal qty

5+2=75+2=7

5+7=125+7=12

LCM of 12 & 7 is 84

X=5x+2x=84X=5x+2x=84 so 84/x=1284/x=12

new proportion of X=60:24X=60:24

Y=5x+7x=84Y=5x+7x=84 so 84/12=784/12=7

new proportion of Y=35:49Y=35:49

Z=X+YZ=X+Y

Z=60+35:24+49Z=60+35:24+49

Z=95:73Z=95:73


Related Questions:

A mixture contains alcohol and water in the ratio 4:3. If 5 litres of water is added to the mixture the ratio becomes 4:5. Find the quantity of alcohol in the given mixture :
Choose the best alternative 68: 130 :: ..... : 350
4a = 6b = 8c ആയാൽ a : b : c =
K, L and M invest sum in the ratio 15 : 20 : 27 respectively. If they earned total profit of Rs. 10230 at the end of year, then what is the difference between share of K and L?
The sum of three numbers is 100. The ratio of the first number to the second number is 4: 9 and the ratio of the second to the third number is 3: 4. Find the second number.