9 added to the product of two consecutive multiples of 6 gives 729. What are the numbers?

Challenger App

No.1 PSC Learning App

★

★

★

★

★

1M+ Downloads

9 added to the product of two consecutive multiples of 6 gives 729. What are the numbers?

A18, 24

B12, 18

C24,30

D30, 36

Answer:

C. 24,30

Read Explanation:

Let the numbers be X, X + 6

X(X+6)+9=729

$X^2+6X+9=729$

$(X+3)^2=729$

$X+3=\sqrt{729}$

$X+3 = ±27$

$X=27-3=24$

So the numbers are $24,30$

Read more in App

Related Questions:

The sum of the coefficients in the expansion of (1+x)¹⁵ is :

If $x =\sqrt{3} - 1$ and $y =\sqrt{3}+1$ then $\frac{(x^4-y^4)}{(x+y)^2}$ is equal to ?

If (m-n)²=64 and mn=180, then (m+n)² is:

If $x^4+\frac{1}{x^4}=\frac{257}{16}$ then find $\frac{8}{13}(x^3+\frac{1}{x^3})$ , where x>0.

The sum of four times a number and 3 times of another number is 43. The difference of two times the second number from three times of the first number is 11. Find the numbers.