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A water well has height h meters and diameter 21 m. The cost of plastering the well is ₹1,36,125 at the rate of ₹275/m², then find the height of the well. (∏=22/7)

A2.25 m

B5.5 m

C7.5 m

D4.5 m

Answer:

A. 2.25 m

Read Explanation:

We are plastering the inner curved surface of the well (a cylinder).

Surface area of cylinder

Curved surface area = (2πrh)( 2\pi r h )

Here, diameter = 21 m ⇒ radius ( r = 10.5 ) m

Use cost formula

Cost=Area×rate\text{Cost} = \text{Area} \times \text{rate}

136125=2×227×10.5×h×275136125 = 2 \times \frac{22}{7} \times 10.5 \times h \times 275

Simplify

2×227×10.5=662 \times \frac{22}{7} \times 10.5 = 66

So,
136125=66×h×275136125 = 66 \times h \times 275
136125=18150h136125 = 18150h

Solve

h=13612518150=7.5h = \frac{136125}{18150} = 7.5

Final Answer:

Height of the well = 7.5 m


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