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Determine the largest 4-digit number that is exactly divisible by 15,25,40 and 75.

A9600

B9975

C9999

D9960

Answer:

A. 9600

Read Explanation:

To find the largest 4-digit number exactly divisible by 15, 25, 40, and 75, follow these steps:

Prime factorization:

(15=3×5)(15 = 3 \times 5)

(25=52)(25 = 5^2)

(40=23×5)(40 = 2^3 \times 5)

(75 = 3 \times 5^2)#

LCM takes highest powers:

\text{LCM} = 2^3 \times 3 \times 5^2 = 8 \times 3 \times 25 = 600</p><h3style="color:rgb(0,0,0);"></h3><pdatapxy="true"style="color:rgb(0,0,0);margintop:2px;marginbottom:2px;">Largest4digitnumber=9999</p><pdatapxy="true"style="color:rgb(0,0,0);margintop:2px;marginbottom:2px;"><br></p><h3 style="color: rgb(0,0,0);"></h3><p data-pxy="true" style="color: rgb(0,0,0); margin-top: 2px; margin-bottom: 2px;">Largest 4-digit number = 9999</p><p data-pxy="true" style="color: rgb(0,0,0); margin-top: 2px; margin-bottom: 2px;"><br>\frac{9999}{600} \approx 16.66</p><pdatapxy="true"style="color:rgb(0,0,0);margintop:2px;marginbottom:2px;">Sothegreatestintegermultipleis<b>16</b>:<br><br></p><p data-pxy="true" style="color: rgb(0,0,0); margin-top: 2px; margin-bottom: 2px;">So the greatest integer multiple is <b>16</b>:<br><br>600 \times 16 = 9600$

9600 is the largest 4-digit number exactly divisible by 15, 25, 40, and 75.


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