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Evaluate: 41 - [21 - {11 - (15 - 6 ÷ 2 × 2)}]

A24

B17

C22

D19

Answer:

C. 22

Read Explanation:

The value is 22.


We solve this expression by working from the innermost brackets outward:

  1. Step 1: Inside the Round Brackets ()( )
    First, perform division, then multiplication, and finally subtraction:

    • Division: 6÷2=36 \div 2 = 3

    • Multiplication: 3×2=63 \times 2 = 6

    • Subtraction: 156=915 - 6 = 9

    The expression becomes:
    41[21{119}]41 - [21 - \{11 - 9\}]

  2. Step 2: Inside the Curly Brackets {}\{ \}

    • Subtract the numbers: 119=211 - 9 = 2

    The expression becomes:
    41[212]41 - [21 - 2]

  3. Step 3: Inside the Square Brackets [][ ]

    • Subtract the numbers: 212=1921 - 2 = 19

    The expression becomes:
    411941 - 19

  4. Step 4: Final Subtraction

    • 4119=2241 - 19 = 22


Related Questions:

Evaluate: 16 + 10 ÷ 5 - 2 × 3

Find the value of

[(23×16)×[3÷3×(1913)3]][(23 \times 16)\times[3 \div 3 \times \frac{(19-13)}{3}]]

154+8×3+5:15 - 4 + 8 \times 3 + 5:

What will come in the place of the question mark (?) in the following equation, if "+' and '-' are interchanged and 'x' and '÷' are interchanged? 18 ÷ 5 + 26 - 45 x 5 = ?
Evaluate: 2 × {17 - 2 × (10 -5)}