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Evaluate: 41 - [21 - {11 - (15 - 6 ÷ 2 × 2)}]

A24

B17

C22

D19

Answer:

C. 22

Read Explanation:

The value is 22.


We solve this expression by working from the innermost brackets outward:

  1. Step 1: Inside the Round Brackets ()( )
    First, perform division, then multiplication, and finally subtraction:

    • Division: 6÷2=36 \div 2 = 3

    • Multiplication: 3×2=63 \times 2 = 6

    • Subtraction: 15−6=915 - 6 = 9

    The expression becomes:
    41−[21−{11−9}]41 - [21 - \{11 - 9\}]

  2. Step 2: Inside the Curly Brackets {}\{ \}

    • Subtract the numbers: 11−9=211 - 9 = 2

    The expression becomes:
    41−[21−2]41 - [21 - 2]

  3. Step 3: Inside the Square Brackets [][ ]

    • Subtract the numbers: 21−2=1921 - 2 = 19

    The expression becomes:
    41−1941 - 19

  4. Step 4: Final Subtraction

    • 41−19=2241 - 19 = 22


Related Questions:

48−12×3+910−9÷3\frac{48-12 \times 3 + 9}{10 - 9 \div 3} = _____

Find (125+95)^2 - 4x125x95 :

Find the value of

[(30÷5)×{306+191×(4−3)}]\left[ (30 \div 5) \times \left\{ \frac{30}{6} + \frac{19}{1} \times (4 - 3) \right\} \right]

Evaluate: 41 - [36 - {48 ÷ 2 - (6 - 12 ÷ 2) ÷ 2}]
Evaluate: 41 - [21 - {11 - (15 - 6 ÷ 3 × 3)}]