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21001+299921000−2998=?\frac{2^{1001}+2^{999}}{2^{1000}-2^{998}}=?

A1

B3

C5

Dഇവയൊന്നുമല്ല

Answer:

D. ഇവയൊന്നുമല്ല

Read Explanation:

The value of the expression is 103\frac{10}{3} (or 3133\frac{1}{3}).

1. Identify the smallest power of 2
To simplify the fraction easily, look for the smallest exponent in the entire expression, which is 998998. We can factor out 29982^{998} from both the numerator and the denominator.

2. Factor the numerator
21001+2999=2998⋅(23+21)2^{1001} + 2^{999} = 2^{998} \cdot (2^3 + 2^1)
=2998⋅(8+2)= 2^{998} \cdot (8 + 2)
=2998⋅10= 2^{998} \cdot 10

3. Factor the denominator
21000−2998=2998⋅(22−1)2^{1000} - 2^{998} = 2^{998} \cdot (2^2 - 1)
=2998⋅(4−1)= 2^{998} \cdot (4 - 1)
=2998⋅3= 2^{998} \cdot 3

4. Simplify the fraction
Now substitute these back into the original problem:
21001+299921000−2998=2998⋅102998⋅3\frac{2^{1001}+2^{999}}{2^{1000}-2^{998}} = \frac{2^{998} \cdot 10}{2^{998} \cdot 3}

Cancel out the common 29982^{998} term from both the top and the bottom:
=103= \frac{10}{3}


Related Questions:

(5001)2(5001)^2 – (4999)2(4999)^2 ന്റെ മൂല്യം

(113+202−3)13=?(11^3+20^2-3)^{\frac{1}{3}}=?

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ചെറുതാക്കുക:

(8)23×(27)23(8)^{\frac{2}{3}}\times(27)^{\frac{2}{3}}