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3025+23310+?=(22)2\sqrt{30\frac25+23\frac{3}{10}+?}=(2\sqrt{2})^2

ആയാൽ? ൻ്റെ സ്ഥാനത്തുള്ള സംഖ്യ ഏത് ?

A10 ³/10

B8⅘

C10 ⁷/10

D7⅖

Answer:

A. 10 ³/10

Read Explanation:

3025+23310+?=(22)2\sqrt{30\frac25+23\frac{3}{10}+?}=(2\sqrt{2})^2

1525+23310+?=8\sqrt{\frac{152}{5}+\frac{233}{10}+?}=8

304+23310+?=8\sqrt{\frac{304+233}{10}+?}=8

53710+?=82=64\frac{537}{10}+?=8^2=64

?=6453710?=64-\frac{537}{10}

=64053710=\frac{640-537}{10}

=10310=\frac{103}{10}

=10310=10\frac{3}{10}


Related Questions:

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√ X + √ 64 = 9.1 ആയാൽ x ന്റെ വില എന്ത്? 

753253752+75×25+252\frac{75^3-25^3}{75^2+75\times25+25^2}

$$ൻ്റെ വില എത്ര ?



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