AB = 6, AC = 3, ∠ BAC = 60 ആയ വശങ്ങളുള്ള സമാന്തര ചതുർഭുജത്തിന്റെ വിസ്തീർണ്ണം കണ്ടെത്തുക.

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Find the area of a parallelogram with sides B = 6, AC = 3, and ∠ BAC = 60.

A12

B9√3

C18

Answer:

Area = ab × sinx

= 6 × 3 × sin60

= 6 × 3 ×√3/2

= 9√3

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