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What is the number of rounds that a wheel of diameter 811m\frac{8}{11}m will make in traversing 10 km?

A4375

B2375

C1000

D4000

Answer:

A. 4375

Read Explanation:

Solution:

Distance=Circumference×No.ofRevolutionDistance=Circumference\times{No.of Revolution}

Distance = 10 km

Diameter=811mDiameter =\frac{8}{11}m

Radius=8112Radius=\frac{\frac{8}{11}}{2}

Radius,r=411Radius,r=\frac{4}{11}

Circumference of Wheel = 2πr2\pi{r}

=2×227×411= 2\times{\frac{22}{7}}\times{\frac{4}{11}}

=167=\frac{16}{7}

16

10km=167×No.ofRevolution10km=\frac{16}{7}\times{No.of Revolution}

No.ofRevolution=716×10000No.of Revolution=\frac{7}{16}\times{10000}

=4375=4375


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