What is the number of rounds that a wheel of diameter 811m\frac{8}{11}m118m will make in traversing 10 km? A4375B2375C1000D4000Answer: A. 4375 Read Explanation: Solution:Distance=Circumference×No.ofRevolutionDistance=Circumference\times{No.of Revolution}Distance=Circumference×No.ofRevolutionDistance = 10 kmDiameter=811mDiameter =\frac{8}{11}mDiameter=118mRadius=8112Radius=\frac{\frac{8}{11}}{2}Radius=2118Radius,r=411Radius,r=\frac{4}{11}Radius,r=114Circumference of Wheel = 2πr2\pi{r}2πr=2×227×411= 2\times{\frac{22}{7}}\times{\frac{4}{11}}=2×722×114=167=\frac{16}{7}=7161610km=167×No.ofRevolution10km=\frac{16}{7}\times{No.of Revolution}10km=716×No.ofRevolutionNo.ofRevolution=716×10000No.of Revolution=\frac{7}{16}\times{10000}No.ofRevolution=167×10000=4375=4375=4375 Read more in App