Challenger App

No.1 PSC Learning App

1M+ Downloads
The price of fuel decreases by 40%, 10% and 50% in three successive months, but increases by 50% in the fourth month. What is the percentage increase/decrease in the price of fuel in the fourth month as compared to its original price?

AIncreases by 57.3%

BDecrease by 59.5%

CIncreases by 56.29%

DDecreases by 61.17%

Answer:

B. Decrease by 59.5%

Read Explanation:

Let the original price be 100

Let the original price of fuel = 100 units (for simplicity).

First month: decrease by 40%

10040100 - 40% \text{ of } 100 = 100 - 40 = 60

Second month: decrease by 10%

601060 - 10% \text{ of } 60 = 60 - 6 = 54

Third month: decrease by 50%

545054 - 50% \text{ of } 54 = 54 - 27 = 27

Fourth month: increase by 50%

27+5027 + 50% \text{ of } 27 = 27 + 13.5 = 40.5

Original price = 100
New price after 4 months = 40.5
Percentage change=40.5100100×100percent=59.5100×100\text{Percentage change} = \frac{40.5 - 100}{100} \times 100 percent= \frac{-59.5}{100} \times 100 % = -59.5%

The price decreased by 59.5% compared to the original price.

= 22$



Related Questions:

The LCM of three numbers is 2400. If the numbers are in the ratio of 3 : 4 : 5, find the greatest number among them.
The highest common factor of 84 and 108 is:
The smallest natural number which is divisible by 24, 58, 48 and 12 is:
Find the HCF of 153, 117 and 405.
The largest number that can divide 147,183 and 271 leaving remainders 11,13 and 16, respectively, is: