App Logo

No.1 PSC Learning App

1M+ Downloads
ഒരു ത്രികോണത്തിന്റെ വശങ്ങൾ 3 : 4 : 5 എന്ന അംശബന്ധത്തിലാണ്. ത്രികോണത്തിന്റെ ചുറ്റളവ് 120 cm ആയാൽ, ഏറ്റവും നീളം കുറഞ്ഞ വശത്തിന്റെ അളവ് എത്ര ?

A30 cm.

B15 cm

C40 cm

D50 cm

Answer:

A. 30 cm.

Read Explanation:

വശങ്ങൾ = 3x , 4x , 5x ചുറ്റളവ് = 120 cm ചുറ്റളവ് = 12x = 120 x = 10 നീളം കുറഞ്ഞ വശത്തിന്റെ അളവ് = 3x = 30


Related Questions:

A and B invest in a business in the ratio 3 : 2. If 5% of the total profit goes to charity and A's share is Rs. 855, the total profit isA and B invest in a business in the ratio 3 : 2. If 5% of the total profit goes to charity and A's share is Rs. 855, the total profit is
After spending 1/4th of pocket money on chocolates and 1/8th of pizza, a girl is left with Rs. 40. How much money did she have at first?
An amount of sum is to be divided between A, B and C in the ratio of 1 : 3 : 4 in this month and the difference between B and C’s share is Rs. 1600. If the total amount becomes twice the next month, find the total amount of the sum in the next month.
A:B= 8:9 , B:C= 15: 16 ആയാൽ A: C= എത്ര ?
If 9:12:: 12: x, and 28: 42:: 42: y, then the value of 2x + y is: