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The total number of three digit numbers divisible by 3 or 5 is ____.

A440

B300

C100

D420

Answer:

D. 420

Read Explanation:

Solution:

Calculation:

The number which divisible by 3 =Last termFirst term3+1=9991023+1=300=\frac{Last~ term - First ~term}{3} +1=\frac{999-102}{3}+1=300

The number which divisible by 5 =Last termFirst term5+1=9951005+1=180=\frac{Last~ term - First ~term}{5} +1=\frac{995-100}{5}+1=180

The number which divisible by 15 =Last termFirst term15+1=99010515+1=60=\frac{Last~ term - First ~term}{15} +1=\frac{990-105}{15}+1=60

So, the total number of three-digit numbers divisible by 3 or 5 = 300 + 180 - 60 = 420.

 The correct answer is 420.


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