Challenger App

No.1 PSC Learning App

★
★
★
★
★
1M+ Downloads
A train runs at a speed of 111 kmph to cover a distance of 222 km and then at a speed of 86 kmph to cover a distance of 258 km. Find the average speed of the train for the entire distance.

A117 kmph

B96 kmph

C72 kmph

D86 kmph

Answer:

B. 96 kmph

Read Explanation:

Let's break down the problem step-by-step:

1. Calculate the time taken for the first part of the journey:

  • Distance (d1) = 222 km

  • Speed (s1) = 111 kmph

  • Time (t1) = Distance / Speed = 222 km / 111 kmph = 2 hours

2. Calculate the time taken for the second part of the journey:

  • Distance (d2) = 258 km

  • Speed (s2) = 86 kmph

  • Time (t2) = Distance / Speed = 258 km / 86 kmph = 3 hours

3. Calculate the total distance traveled:

  • Total Distance (D) = d1 + d2 = 222 km + 258 km = 480 km

4. Calculate the total time taken:

  • Total Time (T) = t1 + t2 = 2 hours + 3 hours = 5 hours

5. Calculate the average speed:

  • Average Speed = Total Distance / Total Time = 480 km / 5 hours = 96 kmph

Therefore, the average speed of the train for the entire distance is 96 kmph.


Related Questions:

A train overtakes two persons walking along a railway track. The first one walks at 5.4 km/h. The other one walks at 10.8 km/h. The train needs 5.1 and 6.8 seconds respectively to overtake them. What is the speed of the train if both the persons are walking in the same direction as the train?
മണിക്കൂറിൽ 108 കിലോമീറ്റർ വേഗത്തിൽ ഓടുന്ന തീവണ്ടി, 470 മീറ്റർ നീളമുള്ള പാലം കടക്കാൻ 20 സെക്കന്റ്റ് സമയം എടുത്താൽ തീവണ്ടിയുടെ നീളം എത്ര?
125 മീറ്റർ നീളമുള്ള ഒരു ട്രെയിൻ മണിക്കൂറിൽ 30 കി. മീ. സഞ്ചരിക്കുന്നു. അത് പ്ലാറ്റ്ഫോമിലെ ഒരു വിളക്കുമരം എപ്പോൾ കടക്കും?
Train A leaves station M at 7:20 AM and reaches station N at 2:20 PM on the same day. Train B leaves station N at 9:20 AM and reaches station M at 2:20 PM on the same day. Find the time when Trains A and B meet.
A 340 m long train crosses a man walking at a speed of 4.5 km/h in the opposite direction in 6 seconds. What is the speed (in km/h) of the train?