If $81^{-4} ext{ ÷ }729^{(2-x)}=9^{4x}$, then x =

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$81^{-4}\div 729^{(2-x)}=9^{4x}$ എങ്കിൽ x =

A-12

B-14

C-16

D-10

Answer:

$81^{-4}\div 729^{(2-x)}= 9 ^{4x}$

$(9^2)^{-4} \div (9^3)^{(2-x)}$

$a^m \div a^n = a ^{m-n}$

$9^{-8} \div 9^{3(2-x)} = 9^{4x}$

$-8-(3(2-x))=4x$

$-8-(6-3x)=4x$

$-8-6+3x=4x$

$-14=x$

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